
Question #1565c - Socratic
Apr 22, 2015 · The molarity of the silver nitrate solution is 0.394 mM. The balanced chemical equation for this double replacement reaction looks like this AgN O3(aq) +KCl(aq) → AgCl(s) …
Determine the formula of A. Molarity B. Molality C. Mole ... - Socratic
Well, "molarity" is simply the quotient..."molarity"="moles of solute"/"volume of solution" And "molality"="moles of solute"/"kilograms of solvent"... For most, dilute, AQUEOUS solutions, …
Question #c79f3 - Socratic
As you know, molarity is a measure of the number of moles of solute, which in your case would be phosphoric acid, present in
Question #9d6d5 - Socratic
Since molarity is defined as number of moles of solute per liter of solution, decreasing the volume of the solution while keeping the number of moles of solute constant will increase the …
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What is the molarity of a stock solution if 10 mL is diluted to 400 mL with a concentration of 0.5M?
What is the mass in grams of "CaCl"_2" in a "3 M CaCl"_2 ... - Socratic
Aug 24, 2017 · Molarity = mol solute liter of solution A 3 M solution of calcium chloride contains 3 moles of the solute CaCl2 in one liter of solution. To convert 3 mol CaCl2 to mass in grams, …
Question #03339 - Socratic
b) Molarity "Molarity" = "moles of solute"/"litres of solution" The volume of a liquid changes with temperature, so molarity is affected by temperature. c) Normality "Normality" = "equivalents of …
Question #85f29 - Socratic
In essence, molarity is a measure of concentration that deals with moles of solute and liters of solution. This means that a solution's molarity can be used as a conversion factor that can …
Question #b28e9 - Socratic
Apr 15, 2016 · "1.4 L" The idea here is that you need to use the molarity and volume of the target solution to determine how many moles of solute it contains. Since you're dealing with a …
Question #a14ed - Socratic
Since molarity is defined as the number of moles of solute per liter of solution, increasing the volume while keeping the number of moles of solute constant will result in a decrease in …