
Is it necessary to have oh group of phenol valways at ortho
No, the "OH" group in phenol is by definition at "C1". > The structure of phenol is You can draw the structure like this: phenol2 However, the structure is not meta-phenol. It is phenol because …
On the hydrolysis of esters according to the reaction: HCOO
Nov 26, 2017 · HCOO^(-)(aq) + H_2O(l) rightleftharpoons HCOOH(aq) + OH^(-)(aq) If the solution is diluted, the reaction will shift left, because (i) water isn't in the equilibrium expression, and …
Can you give the IUPAC name for the following (CH_3)_3C-OH
Aug 29, 2016 · So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by …
6-10. What are the name of the following compounds? a. Ca …
Generally, OH adds "hydroxide" to an inorganic compound's name. Moreover, element names aren't capitalized unless at the beginning of a sentence. We write iron (II) hydroxide instead of …
Question #477c5 - Socratic
On the product side the Carbonic Acid (#H_2CO_3#) is the Conjugate Acid as it is the hydrogen donor to the Conjugate Base (#OH^-#) as it receives the hydrogen ion.
Question #bcb2d - Socratic
calculate moles of Acid, calculate moles of Base. subtract, #OH^-# should be in excess, calculate Molarity of #OH^-# , pOH = -log (#OH^-#), then 14-pOH = pH
Question #74006 - Socratic
(d) is the correct option. CH_3CH(OH)CH_2CH_2CH_3 (pentan-2-ol) being secondary alcohol on oxidation first tansformed into ketone. CH_3CH(OH)CH_2CH_2CH_3stackrel([O])-> …
Question #c76b8 - Socratic
Answer below Calcium oxide will dissolve to produce Calcium Hydroxide. It is as follows: CaO + H_2O to Ca (OH)_2 In essence: "base + water" to "alkali"
Question #5392e - Socratic
Dec 13, 2017 · Here's what I get. Step 1. Write the molecular equation "Fe" ("NO"_3)_3" (aq)"+ "3NH"_3" (aq)" + "3H"_2"O (l)" → "Fe (OH)"_3" (s)" + "3NH"_4"NO"_3" (aq)" Step 2 ...
Question #2c594 - Socratic
The molar concentration of the ammonia is 0.015 mol/L. > Your textbook is misleading you. The 57.6 % figure is calculated as if the ammonia were in the form of "NH"_4"OH". Also, the …