What is the equation in standard form of the parabola with a focus at (-18,30) and a directrix of y= 22?

Mar 22, 2018 · (x-5)^2+(y+2)^2=(sqrt12)^2 is a circle with center (5,-2) and radius sqrt12 This is a quadratic equation in two variables, where one - coefficients of x^2 and y^2 are equal and two - the …

The standard equation of horizontal parabola is (y-2)^2 = 18 (x-1.5) Focus is at (6,2) and directrix is x=-3. Vertex is at midway between focus and directrix. Therefore vertex is at ( (6-3)/2,2) or (1.5,2).Here …

How do you write the equation of a line in slope intercept, point slope and standard form given (2,-3) and (4,-1)? Algebra Forms of Linear Equations Write an Equation Given Two Points

What is the standard form of the parabola with a vertex at (3,6) and a focus at (3,3)?

How do you write a polynomial in standard form, then classify it by degree and number of terms 8 − 6w − 12w − 8w2 − 7 − 3w3?

To begin writing this in standard form, first, multiply the two terms within parenthesis. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right …

Explanation: We know that the Standard Equation (eqn.) of the Parabola with Vertex at the Origin # (0,0)# and the Focus at # (0,b)# is,

-2x^3 - 31x^2 - 184x - 512 (x - x^2) (x + 8) - (x + 8)^3 - (x + 8) [x^2 - x + (x + 8)^2] - (x + 8) (x^2 - x + x^2 + 16x + 64) - (x + 8) (2x^2 + 15x + 64) -2x^3 - 31x ...

How do you write the standard form of the equation of the parabola that has (-1/4, 3/2) vertex and (-2,0) point?